A calorimeter holds 50 g water at 22.0°C. A sample of hot iron is added to the water. The final temperature of the water and iron is 28.0°C. What is the change in enthalpy associated with the change in the water’s temperature?
Note: The specific heat of water is 4.18 J/°C

Use the formula ΔH = - cmΔT
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nikitarahangdaleVT 6 months ago
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The change in enthalpy associated with the change in the water’s temperature is 1254 J.

What is specific heat?

The amount of heat required to increase the temperature of one gram of a substance by one Celsius degree is known as specific heat.

Enthalpy change will be calculated as:

ΔH = -cmΔT, where

m = mass of water = 50g

c = specific heat of water = 4.18J/g°C

ΔT = change in temperature = 28 - 22 = 6 °C

On putting values in the above equation, we get

ΔH = -(4.18)(50)(6) = -1254 J

Hence change in enthalpy of the reaction is -1254 J.

To know more about enthalpy change, visit the below link:

https://brainacademy.pro/question/11628413

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