Note: The specific heat of water is 4.18 J/°C
Use the formula ΔH = - cmΔT
The change in enthalpy associated with the change in the water’s temperature is 1254 J.
What is specific heat?
The amount of heat required to increase the temperature of one gram of a substance by one Celsius degree is known as specific heat.
Enthalpy change will be calculated as:
ΔH = -cmΔT, where
m = mass of water = 50g
c = specific heat of water = 4.18J/g°C
ΔT = change in temperature = 28 - 22 = 6 °C
On putting values in the above equation, we get
ΔH = -(4.18)(50)(6) = -1254 J
Hence change in enthalpy of the reaction is -1254 J.
To know more about enthalpy change, visit the below link: