A calorimeter holds 50 g water at 22.0°C. A sample of hot iron is added to the water. The final temperature of the water and iron is 28.0°C. What is the change in enthalpy associated with the change in the water’s temperature?

Note: The specific heat of water is 4.18 J/°C

Use the formula ΔH = - cmΔT

Note: The specific heat of water is 4.18 J/°C

Use the formula ΔH = - cmΔT

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The change in

enthalpyassociated with the change in thewater’s temperatureis 1254 J.## What is specific heat?

The amount of

heatrequired to increase thetemperatureof onegramof asubstanceby one Celsiusdegreeis known asspecific heat.Enthalpy changewill be calculated as:ΔH = -cmΔT, wherem = massof water = 50gc = specific heatof water = 4.18J/g°CΔT= change intemperature= 28 - 22 = 6 °COn putting values in the above equation, we get

ΔH= -(4.18)(50)(6) = -1254 JHence change in

enthalpyof thereactionis -1254 J.To know more about

enthalpy change, visit the below link:https://brainacademy.pro/question/11628413

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