A gas occupies 500.0 mL at 30.00°C and 70.00 kPa. What will the volume be at SC?
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nuhulawal20 6 months ago
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Given the initial volume, temperature and pressure of the gas, at Standard conditions for temperature and pressure, the new volume will be 310mL.

What is combined gas law?

Combined gas law put together both Boyle's Law, Charles's Law, and Gay-Lussac's Law. It states that "the ratio of the product of volume and pressure and the absolute temperature of a gas is equal to a constant.

It is expressed as;

P₁V₁/T₁ = P₂V₂/T₂

Given the data in the question;

  • Initial volume V₁ = 500mL = 0.5L
  • Initial pressure P₁ = 0.690846atm
  • Initial temperature T₁ = 30.00°C = 303.15K

At Standard conditions for temperature and pressure

  • Final pressure P₂ = 1.0atm
  • Final temperature T₂ = 273.15K
  • Final volume V₂ = ?

To calculate the new volume the gas, we substitute our given values into the expression above.

P₁V₁/T₁ = P₂V₂/T₂

P₁V₁T₂ = P₂V₂T₁

V₂ = P₁V₁T₂ / P₂T₁

V₂ = ( 0.690846atm × 0.5L × 273.15K )  / ( 1.0atm × 303.15K )

V₂ = 94.3522925LatmK / 303.15atmK

V₂ = 0.31L

V₂ = 310mL

Given the initial volume, temperature and pressure of the gas, at Standard conditions for temperature and pressure, the new volume will be 310mL.

Learn more about the combined gas law here: brainacademy.pro/question/25944795

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