A gas occupies 500.0 mL at 30.00°C and 70.00 kPa. What will the volume be at SC?
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nuhulawal20 6 months ago
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Given the initial volume, temperature and pressure of the gas, at Standard conditions for temperature and pressure, the new volume will be 310mL.

### What is combined gas law?

Combined gas law put together both Boyle's Law, Charles's Law, and Gay-Lussac's Law. It states that "the ratio of the product of volume and pressure and the absolute temperature of a gas is equal to a constant.

It is expressed as;

P₁V₁/T₁ = P₂V₂/T₂

Given the data in the question;

• Initial volume V₁ = 500mL = 0.5L
• Initial pressure P₁ = 0.690846atm
• Initial temperature T₁ = 30.00°C = 303.15K

At Standard conditions for temperature and pressure

• Final pressure P₂ = 1.0atm
• Final temperature T₂ = 273.15K
• Final volume V₂ = ?

To calculate the new volume the gas, we substitute our given values into the expression above.

P₁V₁/T₁ = P₂V₂/T₂

P₁V₁T₂ = P₂V₂T₁

V₂ = P₁V₁T₂ / P₂T₁

V₂ = ( 0.690846atm × 0.5L × 273.15K )  / ( 1.0atm × 303.15K )

V₂ = 94.3522925LatmK / 303.15atmK

V₂ = 0.31L

V₂ = 310mL

Given the initial volume, temperature and pressure of the gas, at Standard conditions for temperature and pressure, the new volume will be 310mL.