Initially, both blocks have gravitational potential energy, which is then converted to kinetic energy.

Recall:

U = Potential Energy (J) m = mass (kg) g = acceleration due to gravity (m/s²)

h = height (m)

And at the end, block 2 has both kinetic and potential energy. Kinetic is defined as:

v = velocity (m/s)

We can do a summation of initial and final forces.

Initial:

Final:

Set the two equal (no energy loss in this situation) and solve for velocity.

**This can be solved in a simpler way using a summation of forces.

B.

Now, we can do a summation of forces to solve. First, we must solve for the acceleration of the system now that we have found the velocity. Use the kinematic equation:

Initial velocity is 0 m/s, so:

Now, we can use a summation of forces for any block. We can do block 1:

Hi there!

A.

We can use the

work-energytheorem to solve.Initially, both blocks have

gravitational potential energy, which is then converted tokinetic energy.Recall:

U = Potential Energy (J)

m = mass (kg)

g = acceleration due to gravity (m/s²)

h = height (m)

And at the end, block 2 has both kinetic and potential energy. Kinetic is defined as:

v = velocity (m/s)

We can do a summation of initial and final forces.

Initial:

Final:

Set the two equal (no energy loss in this situation) and solve for velocity.

**This can be solved in a simpler way using a

summation of forces.B.

Now, we can do a summation of forces to solve. First, we must solve for the acceleration of the system now that we have found the velocity. Use the kinematic equation:

Initial velocity is 0 m/s, so:

Now, we can use a summation of forces for any block. We can do block 1:

Using Newton's Second Law: