How many kilograms are present in 6.78x1025molecules of Al2(SO4)3? (hint 1kg=103g)

Atomic masses:

Al = 27

S = 32

O = 16

A) 0.891kg

B) 38.5kg

C) Cannot be determined

D) 8.44kg
Answer
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indrawboy 7 months ago
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mol = 6.78 x 10²⁵ : 6.02 x 10²³ = 112.62

MM Al₂(SO₄)₃ = 2.27 + 3.32+12.16 =342 g/mol

mass = 112.62 x 342 = 38516.04 g = 38.5 kg

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