The angle 01, is located in Quadrant II, and cos(01) = -12/19
What is the value of sin(01)?
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piratepower12 7 months ago
Светило науки - 38 ответа - 0 помощи



Step-by-step explanation:

Ok so insead of using 01 as the angle ill use x. cos(θ) is the the x-value of the point on the unit circle, while sin(θ) is the y value. cos(x) here is -12/19. By constructing a triangle such that one of the verticies is at (-12/19, sin(x)), we know the x distance is -12/19, and the hypotenues is 1, because it's a unit circle. sqrt(1-144/361)=sqrt(217/361)=sqrt(217)/19. the y value must e positive because this point lays in the 2nd quadrant.

my explanation might be a but tricky so let me know if you have any questions.

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