Jacobs school is selling tickets to a fall musical. First day of ticket sales the school sold 28 tickets. If adult tickets cost $8 each and child tickets cost $5, how many adult and child tickets were sold? Total ticket sales: $176

x is the amount of adult tickets y is the amount of child tickets ----------------------------------------------------------

lets make 2 equations: 1) x + y = 28 2) 8x + 5y = 176 ----------------------------------------------------------

now we can substitute either x or y into the second equation so that we only have to deal with one variable at once.

x + y = 28 subtract y from each side: x + y - y = 28 - y which gives you: x = 28 - y -------------------------------------------------------

Then we plug that into the second equation, which will give us:

8(28 - y) + 5y = 176

now you want to expand 8(28 - y), so you use the distributive property.

8(28 - y) = 8*28 - 8*y = 224 - 8y

now that we have solved that, plug it back into the equation:

224 - 8y + 5y = 176

subtract 224 from each side:

224 - 8y + 5y - 224 = 176 -224

which gives us: -3y = -48

now if you multiply each side by ( -1 ) you get: 3y = 48

now divide both sides by 3 and you get: y = 48 / 3

48 / 3 is 16

y = 16 -------------------------------------------------------------------------------

now plug y = 16 into equation 1

equation 1 was x + y = 28

plug 16 in for y which gives us:

x + 16 = 28

subtract 16 from both sides

x + 16 - 16 = 28 - 16

Which finally gives us x = 12 ---------------------------------------------------------------------------------

Remember: x is the amount of adult tickets y is the amount of child tickets

x = 12 means that 12 adult tickets were sold y = 16 means that 16 child tickets were sold ----------------------------------------------------------------------------------

if my answer is not correct, please reach out to me :)

Answer:12 adult tickets, 16 child ticketsStep-by-step explanation:x is the amount of adult tickets

y is the amount of child tickets

----------------------------------------------------------

lets make 2 equations:

1) x + y = 28

2) 8x + 5y = 176

----------------------------------------------------------

now we can substitute either x or y into the second equation so that we only have to deal with one variable at once.

x + y = 28

subtract y from each side:

x + y - y = 28 - y

which gives you:

x = 28 - y

-------------------------------------------------------

Then we plug that into the second equation, which will give us:

8(28 - y) + 5y = 176

now you want to expand 8(28 - y), so you use the distributive property.

8(28 - y) = 8*28 - 8*y = 224 - 8y

now that we have solved that, plug it back into the equation:

224 - 8y + 5y = 176

subtract 224 from each side:

224 - 8y + 5y - 224 = 176 -224

which gives us:

-3y = -48

now if you multiply each side by ( -1 ) you get:

3y = 48

now divide both sides by 3 and you get:

y = 48 / 3

48 / 3 is 16

y = 16

-------------------------------------------------------------------------------

now plug y = 16 into equation 1

equation 1 was x + y = 28

plug 16 in for y which gives us:

x + 16 = 28

subtract 16 from both sides

x + 16 - 16 = 28 - 16

Which finally gives us

x = 12

---------------------------------------------------------------------------------

Remember:

x is the amount of adult tickets

y is the amount of child tickets

x = 12 means that 12 adult tickets were sold

y = 16 means that 16 child tickets were sold

----------------------------------------------------------------------------------

if my answer is not correct, please reach out to me :)