A plane leaves airport A and travels 550 miles to airport B on a bearing of N35°E. The plane later leaves airport B and travels to airport C 380 miles away on a
bearing of S72°E. Find the distance from airport A to airport to the nearest tenth of a mile
Answer
0 (0 оценки)
0
unknown111888 6 months ago
Светило науки - 6 ответа - 0 помощи

Answer:

d₃ = 803.9 Miles

Step-by-step explanation:

d₁ = 560 Miles

R₁ = N35⁰E

d₂ = 410 Miles

R₂ = S76⁰E

d₃ = ?

α = 35⁰+76⁰ = 111⁰

We can apply the Law of Cosines as follows

d₃ = √(d₁² + d₂² - 2*d₁*d₂* Cos α)

⇒  d₃ = √(560² + 410² - 2*560*410* Cos 111⁰) = 803.9 Miles

Still have questions?