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For systems of inequalities, graph each system on a coordinate plane to show the solution region. Next, use the graph to answer the question. Be sure to define your variables and show all of your work.

Q.1. The potter at a pottery store makes two sizes of vases. The larger size takes six hours to make, and the smaller size takes 1.5 hours to make. The potter works 30 hours a week. She needs to make at least six total vases a week, including at least two of each size. Give one example of how many of each type of vase the potter can make.
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rspill6 5 months ago
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Answer:

Step-by-step explanation:

Let x and y be the large (x) and small (y) vases the potter makes in one week.

We are told that the large and small vases require 6 hours for each large(x) and 1.5 hours for each small (y) vase.  The combination of large and small vases made in one week thus requires a total time of:

          6x + 1.5y = total hours/week

We are told that the potter works 30 hours per week, so:

        6x + 1.5y = 30 hours

We also learn that she needs to make at least 6 vases in a week, so:

        x + y => 6

Plot the two equations:

6x + 1.5y = 30, and

x + y => 6

This will produce the attached grap, Vases1.  The inequality appears as the shaded area in the upper area.  Any point in the shaded area satisfies the inequality of x + y => 6.  The x and y intercepts are at (0,6) and (6,0), representing either all large (x) or small vases (y).

The lines intersect at (4.67,1.33).  This represents a fictional combination of 4.67 large and 1.33 small vases.  This results in 6 vases (4.67 + 1.33) that require a total of 30 hours to make (6*4.67 + 1.5*1.33) = 30 hours.  If you want to select whole number answers, they appear at (0,6), (2,4), (4,2), and (6,0).  (x,y or large,small).  All combinations result in 6 vases, but eould require less than the 30 hours of time available.  Any whole number combination in the area below the line 6x + 1.5y = 30, but above the line x+y =>6 are valid, such as (4,4).  This area is shown in Vases2.  The valid area for making choices has the darkest shade, where the two inequalities are both satisfied.

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